What are the solutions to the equation -x^2+4x+10=0 ?

The solutions to the equation -x^2+4x+10=0 are x=2-sqrt(14),x=2+sqrt(14)

Find the zeros of -x^2+4x+10=0

The zeros of -x^2+4x+10=0 are x=2-sqrt(14),x=2+sqrt(14)

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- x^{2} + 4 x + 10 = 0

x = 2 - 14, x = 2 + 14

Decimal

x = - 1.74165 \dots, x = 5.74165 \dots

Solution steps

- x^{2} + 4 x + 10 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 4 \pm 4 ^{2} - 4 ( - 1 ) \cdot 10}{2 ( - 1 )}

4^{2} - 4 (- 1) \cdot 10 = 214

x_{1, 2} = \frac{- 4 \pm 2 14}{2 ( - 1 )}

Separate the solutions

x_{1} = \frac{- 4 + 2 14}{2 ( - 1 )}, x_{2} = \frac{- 4 - 2 14}{2 ( - 1 )}

x = \frac{- 4 + 2 14}{2 ( - 1 )} : 2 - 14

x = \frac{- 4 - 2 14}{2 ( - 1 )} : 2 + 14

The solutions to the quadratic equation are:

x = 2 - 14, x = 2 + 14

- 8 x + 96 - 4 x^{2} = 0

4 v^{2} + 20 v = 0

x^{2} + 16 x + 16 = 0

4 x^{2} + 6 x + 9 = 3 x^{2}

\frac{x ^{2}}{6} = 38

What are the solutions to the equation -x^2+4x+10=0 ?
The solutions to the equation -x^2+4x+10=0 are x=2-sqrt(14),x=2+sqrt(14)
Find the zeros of -x^2+4x+10=0
The zeros of -x^2+4x+10=0 are x=2-sqrt(14),x=2+sqrt(14)