What are the solutions to the equation 2+y^2=4 ?

The solutions to the equation 2+y^2=4 are y=sqrt(2),y=-sqrt(2)

Find the zeros of 2+y^2=4

The zeros of 2+y^2=4 are y=sqrt(2),y=-sqrt(2)

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Popular >

2 + y^{2} = 4

y = 2, y = - 2

Decimal

y = 1.41421 \dots, y = - 1.41421 \dots

Solution steps

2 + y^{2} = 4

Move

2

to the right side

y^{2} = 2

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

y = 2, y = - 2

x^{2} - 5 x = 1

x^{2} - 5 x = 5

t^{2} + 9 t = 0

x^{2} - 1 x - 30 = 0

x^{2} - \frac{x}{4}

What are the solutions to the equation 2+y^2=4 ?
The solutions to the equation 2+y^2=4 are y=sqrt(2),y=-sqrt(2)
Find the zeros of 2+y^2=4
The zeros of 2+y^2=4 are y=sqrt(2),y=-sqrt(2)