What are the solutions to the equation 2x^2+x-300=0 ?

The solutions to the equation 2x^2+x-300=0 are x=12,x=-25/2

Find the zeros of 2x^2+x-300=0

The zeros of 2x^2+x-300=0 are x=12,x=-25/2

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2 x^{2} + x - 300 = 0

x = 12, x = - \frac{25}{2}

Decimal

x = 12, x = - 12.5

Solution steps

2 x^{2} + x - 300 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 1 \pm 1 ^{2} - 4 \cdot 2 ( - 300 )}{2 \cdot 2}

1^{2} - 4 \cdot 2 (- 300) = 49

x_{1, 2} = \frac{- 1 \pm 49}{2 \cdot 2}

Separate the solutions

x_{1} = \frac{- 1 + 49}{2 \cdot 2}, x_{2} = \frac{- 1 - 49}{2 \cdot 2}

x = \frac{- 1 + 49}{2 \cdot 2} : 12

x = \frac{- 1 - 49}{2 \cdot 2} : - \frac{25}{2}

The solutions to the quadratic equation are:

x = 12, x = - \frac{25}{2}

16 x^{2} = 8 x - 1

2 x + 5 = x^{2}

x, x^{2} + y^{2} + 5 x - y + 7 = 0

u^{2} - 12 = 7 u

x^{2} + 16 x - 22 = 0

What are the solutions to the equation 2x^2+x-300=0 ?
The solutions to the equation 2x^2+x-300=0 are x=12,x=-25/2
Find the zeros of 2x^2+x-300=0
The zeros of 2x^2+x-300=0 are x=12,x=-25/2