What are the solutions to the equation u^2-12=7u ?

The solutions to the equation u^2-12=7u are u=(7+sqrt(97))/2 ,u=(7-sqrt(97))/2

Find the zeros of u^2-12=7u

The zeros of u^2-12=7u are u=(7+sqrt(97))/2 ,u=(7-sqrt(97))/2

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u^{2} - 12 = 7 u

u = \frac{7 + 97}{2}, u = \frac{7 - 97}{2}

Decimal Notation

u = 8.42442 \dots, u = - 1.42442 \dots

Solution steps

u^{2} - 12 = 7 u

Move

7 u

to the left side

u^{2} - 12 - 7 u = 0

Write in the standard form

a x^{2} + b x + c = 0

u^{2} - 7 u - 12 = 0

Solve with the quadratic formula

u_{1, 2} = \frac{- ( - 7 ) \pm ( - 7 ) ^{2} - 4 \cdot 1 \cdot ( - 12 )}{2 \cdot 1}

(- 7)^{2} - 4 \cdot 1 \cdot (- 12) = 97

u_{1, 2} = \frac{- ( - 7 ) \pm 97}{2 \cdot 1}

Separate the solutions

u_{1} = \frac{- ( - 7 ) + 97}{2 \cdot 1}, u_{2} = \frac{- ( - 7 ) - 97}{2 \cdot 1}

u = \frac{- ( - 7 ) + 97}{2 \cdot 1} : \frac{7 + 97}{2}

u = \frac{- ( - 7 ) - 97}{2 \cdot 1} : \frac{7 - 97}{2}

The solutions to the quadratic equation are:

u = \frac{7 + 97}{2}, u = \frac{7 - 97}{2}

x^{2} + 16 x - 22 = 0

(2 x + 5) (5 x - 2) = 0

x^{2} + 10 x + 25 = 12

x^{2} = 1 0^{2} + 8^{2}

x^{2} - 12 x - 91 = - 6

What are the solutions to the equation u^2-12=7u ?
The solutions to the equation u^2-12=7u are u=(7+sqrt(97))/2 ,u=(7-sqrt(97))/2
Find the zeros of u^2-12=7u
The zeros of u^2-12=7u are u=(7+sqrt(97))/2 ,u=(7-sqrt(97))/2