What are the solutions to the equation x^2=10^2+8^2 ?

The solutions to the equation x^2=10^2+8^2 are x=2sqrt(41),x=-2sqrt(41)

Find the zeros of x^2=10^2+8^2

The zeros of x^2=10^2+8^2 are x=2sqrt(41),x=-2sqrt(41)

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x^{2} = 1 0^{2} + 8^{2}

x = 241, x = - 241

Decimal

x = 12.80624 \dots, x = - 12.80624 \dots

Solution steps

x^{2} = 1 0^{2} + 8^{2}

Simplify

1 0^{2} + 8^{2} : 164

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = 164, x = - 164

164 = 241

- 164 = - 241

x = 241, x = - 241

x^{2} - 12 x - 91 = - 6

(x - 2)^{2} + 3 (3 x - 4) (3 x + 4) = 7 (4 x - 3) - 23

2 x^{2} - 13 x + 2 = 0

x^{2} - 10 x = 0

3 x^{2} - 4 x = 0

What are the solutions to the equation x^2=10^2+8^2 ?
The solutions to the equation x^2=10^2+8^2 are x=2sqrt(41),x=-2sqrt(41)
Find the zeros of x^2=10^2+8^2
The zeros of x^2=10^2+8^2 are x=2sqrt(41),x=-2sqrt(41)