What are the solutions to the equation n(2n+1)=6 ?

The solutions to the equation n(2n+1)=6 are n= 3/2 ,n=-2

Find the zeros of n(2n+1)=6

The zeros of n(2n+1)=6 are n= 3/2 ,n=-2

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n (2 n + 1) = 6

n = \frac{3}{2}, n = - 2

Decimal Notation

n = 1.5, n = - 2

Solution steps

n (2 n + 1) = 6

Expand

n (2 n + 1) : 2 n^{2} + n

2 n^{2} + n = 6

Move

6

to the left side

2 n^{2} + n - 6 = 0

Solve with the quadratic formula

n_{1, 2} = \frac{- 1 \pm 1 ^{2} - 4 \cdot 2 ( - 6 )}{2 \cdot 2}

1^{2} - 4 \cdot 2 (- 6) = 7

n_{1, 2} = \frac{- 1 \pm 7}{2 \cdot 2}

Separate the solutions

n_{1} = \frac{- 1 + 7}{2 \cdot 2}, n_{2} = \frac{- 1 - 7}{2 \cdot 2}

n = \frac{- 1 + 7}{2 \cdot 2} : \frac{3}{2}

n = \frac{- 1 - 7}{2 \cdot 2} : - 2

The solutions to the quadratic equation are:

n = \frac{3}{2}, n = - 2

x, x^{2} + 2 x + 3 = 0

m^{2} = 25

m^{2} = 7 m

X^{2} - X - 12 = 0

x, x^{2} + 4 \cdot x \cdot y - 2 \cdot x + 4 \cdot y^{2} - 4 \cdot y - 3 = 0

What are the solutions to the equation n(2n+1)=6 ?
The solutions to the equation n(2n+1)=6 are n= 3/2 ,n=-2
Find the zeros of n(2n+1)=6
The zeros of n(2n+1)=6 are n= 3/2 ,n=-2