What are the solutions to the equation X^2-X-12=0 ?

The solutions to the equation X^2-X-12=0 are X=4,X=-3

Find the zeros of X^2-X-12=0

The zeros of X^2-X-12=0 are X=4,X=-3

Popular >

X^{2} - X - 12 = 0

X = 4, X = - 3

Solution steps

X^{2} - X - 12 = 0

Solve with the quadratic formula

X_{1, 2} = \frac{- ( - 1 ) \pm ( - 1 ) ^{2} - 4 \cdot 1 \cdot ( - 12 )}{2 \cdot 1}

(- 1)^{2} - 4 \cdot 1 \cdot (- 12) = 7

X_{1, 2} = \frac{- ( - 1 ) \pm 7}{2 \cdot 1}

Separate the solutions

X_{1} = \frac{- ( - 1 ) + 7}{2 \cdot 1}, X_{2} = \frac{- ( - 1 ) - 7}{2 \cdot 1}

X = \frac{- ( - 1 ) + 7}{2 \cdot 1} : 4

X = \frac{- ( - 1 ) - 7}{2 \cdot 1} : - 3

The solutions to the quadratic equation are:

X = 4, X = - 3

x, x^{2} + 4 \cdot x \cdot y - 2 \cdot x + 4 \cdot y^{2} - 4 \cdot y - 3 = 0

- 2 x^{2} + 4 x + 1

- 3 x^{2} + 24 x = 0

3 x^{2} - 10 x - 6 = 0

(x + 3) (x - 2) = - 4

What are the solutions to the equation X^2-X-12=0 ?
The solutions to the equation X^2-X-12=0 are X=4,X=-3
Find the zeros of X^2-X-12=0
The zeros of X^2-X-12=0 are X=4,X=-3