What are the solutions to the equation 2(x-4)(x-4)-18=0 ?

The solutions to the equation 2(x-4)(x-4)-18=0 are x=7,x=1

Find the zeros of 2(x-4)(x-4)-18=0

The zeros of 2(x-4)(x-4)-18=0 are x=7,x=1

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2 (x - 4) (x - 4) - 18 = 0

x = 7, x = 1

Solution steps

2 (x - 4) (x - 4) - 18 = 0

Move

18

to the right side

2 (x - 4) (x - 4) = 18

Simplify

2 (x - 4)^{2} = 18

Divide both sides by

2

\frac{2 ( x - 4 ) ^{2}}{2} = \frac{18}{2}

(x - 4)^{2} = 9

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

x - 4 = 9 : x = 7

Solve

x - 4 = - 9 : x = 1

The solutions to the quadratic equation are:

x = 7, x = 1

X^{2} + 4 X - 6 = 0

y, x = 2 (y - 1)^{2} + 2

x - 1 = x^{2}

s^{2} + 10 = 0

x^{2} = 60 + 4 x

What are the solutions to the equation 2(x-4)(x-4)-18=0 ?
The solutions to the equation 2(x-4)(x-4)-18=0 are x=7,x=1
Find the zeros of 2(x-4)(x-4)-18=0
The zeros of 2(x-4)(x-4)-18=0 are x=7,x=1