What are the solutions to the equation (2x-1)^2=-4 ?

The solutions to the equation (2x-1)^2=-4 are x= 1/2+i,x= 1/2-i

Find the zeros of (2x-1)^2=-4

The zeros of (2x-1)^2=-4 are x= 1/2+i,x= 1/2-i

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(2 x - 1)^{2} = - 4

x = \frac{1}{2} + i, x = \frac{1}{2} - i

Solution steps

(2 x - 1)^{2} = - 4

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

2 x - 1 = - 4 : x = \frac{1}{2} + i

Solve

2 x - 1 = - - 4 : x = \frac{1}{2} - i

The solutions to the quadratic equation are:

x = \frac{1}{2} + i, x = \frac{1}{2} - i

6 v^{2} - 174 v + 600 = 0

2 k^{2} + 7 k + 1 = 0

x^{2} + 3 a x + a^{2} = 0

150000000 x^{2} + x - 0.29 = 0

x (x - 3) = 2 (10 - x)

What are the solutions to the equation (2x-1)^2=-4 ?
The solutions to the equation (2x-1)^2=-4 are x= 1/2+i,x= 1/2-i
Find the zeros of (2x-1)^2=-4
The zeros of (2x-1)^2=-4 are x= 1/2+i,x= 1/2-i