What are the solutions to the equation 2k^2+7k+1=0 ?

The solutions to the equation 2k^2+7k+1=0 are k=(-7+sqrt(41))/4 ,k=(-7-sqrt(41))/4

Find the zeros of 2k^2+7k+1=0

The zeros of 2k^2+7k+1=0 are k=(-7+sqrt(41))/4 ,k=(-7-sqrt(41))/4

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2 k^{2} + 7 k + 1 = 0

k = \frac{- 7 + 41}{4}, k = \frac{- 7 - 41}{4}

Decimal Notation

k = - 0.14921 \dots, k = - 3.35078 \dots

Solution steps

2 k^{2} + 7 k + 1 = 0

Solve with the quadratic formula

k_{1, 2} = \frac{- 7 \pm 7 ^{2} - 4 \cdot 2 \cdot 1}{2 \cdot 2}

7^{2} - 4 \cdot 2 \cdot 1 = 41

k_{1, 2} = \frac{- 7 \pm 41}{2 \cdot 2}

Separate the solutions

k_{1} = \frac{- 7 + 41}{2 \cdot 2}, k_{2} = \frac{- 7 - 41}{2 \cdot 2}

k = \frac{- 7 + 41}{2 \cdot 2} : \frac{- 7 + 41}{4}

k = \frac{- 7 - 41}{2 \cdot 2} : \frac{- 7 - 41}{4}

The solutions to the quadratic equation are:

k = \frac{- 7 + 41}{4}, k = \frac{- 7 - 41}{4}

x^{2} + 3 a x + a^{2} = 0

150000000 x^{2} + x - 0.29 = 0

x (x - 3) = 2 (10 - x)

9 x^{2} - 4 = 7 x^{2} - 7 x

2 x^{2} = - 72

What are the solutions to the equation 2k^2+7k+1=0 ?
The solutions to the equation 2k^2+7k+1=0 are k=(-7+sqrt(41))/4 ,k=(-7-sqrt(41))/4
Find the zeros of 2k^2+7k+1=0
The zeros of 2k^2+7k+1=0 are k=(-7+sqrt(41))/4 ,k=(-7-sqrt(41))/4