What are the solutions to the equation x^2+5=2 ?

The solutions to the equation x^2+5=2 are x=sqrt(3)i,x=-sqrt(3)i

Find the zeros of x^2+5=2

The zeros of x^2+5=2 are x=sqrt(3)i,x=-sqrt(3)i

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x^{2} + 5 = 2

x = 3 i, x = - 3 i

Solution steps

x^{2} + 5 = 2

Move

5

to the right side

x^{2} = - 3

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = - 3, x = - - 3

- 3 = 3 i

- - 3 = - 3 i

x = 3 i, x = - 3 i

w^{2} - w - 2 = 0

x^{2} + 2 = 7

\frac{x + 1}{4} - \frac{x ^{2} - 2}{3} = \frac{x ^{2} - 2}{6} + 1

x^{2} - 14 x + 44 = 0

2 x^{2} = 338

What are the solutions to the equation x^2+5=2 ?
The solutions to the equation x^2+5=2 are x=sqrt(3)i,x=-sqrt(3)i
Find the zeros of x^2+5=2
The zeros of x^2+5=2 are x=sqrt(3)i,x=-sqrt(3)i