What are the solutions to the equation q^2+79=0 ?

The solutions to the equation q^2+79=0 are q=sqrt(79)i,q=-sqrt(79)i

Find the zeros of q^2+79=0

The zeros of q^2+79=0 are q=sqrt(79)i,q=-sqrt(79)i

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q^{2} + 79 = 0

q = 79 i, q = - 79 i

Solution steps

q^{2} + 79 = 0

Move

79

to the right side

q^{2} = - 79

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

q = - 79, q = - - 79

- 79 = 79 i

- - 79 = - 79 i

q = 79 i, q = - 79 i

\frac{27 e ^{7}}{3 e ^{4}}

\frac{X + 1}{2 X - 4} < \frac{1}{\frac{1}{3} X - 1}

x^{2} + 36

2 x - 3 \leq 1

2 (x - 4)^{2} = 2

What are the solutions to the equation q^2+79=0 ?
The solutions to the equation q^2+79=0 are q=sqrt(79)i,q=-sqrt(79)i
Find the zeros of q^2+79=0
The zeros of q^2+79=0 are q=sqrt(79)i,q=-sqrt(79)i