What are the solutions to the equation (5x+2)+(x^2-9)+(x^2-7x+12)=0 ?

The solutions to the equation (5x+2)+(x^2-9)+(x^2-7x+12)=0 are x= 1/2+i 3/2 ,x= 1/2-i 3/2

Find the zeros of (5x+2)+(x^2-9)+(x^2-7x+12)=0

The zeros of (5x+2)+(x^2-9)+(x^2-7x+12)=0 are x= 1/2+i 3/2 ,x= 1/2-i 3/2

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(5 x + 2) + (x^{2} - 9) + (x^{2} - 7 x + 12) = 0

x = \frac{1}{2} + i \frac{3}{2}, x = \frac{1}{2} - i \frac{3}{2}

Solution steps

(5 x + 2) + (x^{2} - 9) + (x^{2} - 7 x + 12) = 0

Refine

2 x^{2} - 2 x + 5 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 2 ) \pm ( - 2 ) ^{2} - 4 \cdot 2 \cdot 5}{2 \cdot 2}

Simplify

(- 2)^{2} - 4 \cdot 2 \cdot 5 : 6 i

x_{1, 2} = \frac{- ( - 2 ) \pm 6 i}{2 \cdot 2}

Separate the solutions

x_{1} = \frac{- ( - 2 ) + 6 i}{2 \cdot 2}, x_{2} = \frac{- ( - 2 ) - 6 i}{2 \cdot 2}

x = \frac{- ( - 2 ) + 6 i}{2 \cdot 2} : \frac{1}{2} + i \frac{3}{2}

x = \frac{- ( - 2 ) - 6 i}{2 \cdot 2} : \frac{1}{2} - i \frac{3}{2}

The solutions to the quadratic equation are:

x = \frac{1}{2} + i \frac{3}{2}, x = \frac{1}{2} - i \frac{3}{2}

x^{2} + 6 x + 58 = 0

s, 12 x^{2} - 8 s x + s^{2} = 0

p^{2} - 16 p - 52 = 0

x^{2} + 8 + 16 = 0

x^{2} - 6 + 8 = 0

What are the solutions to the equation (5x+2)+(x^2-9)+(x^2-7x+12)=0 ?
The solutions to the equation (5x+2)+(x^2-9)+(x^2-7x+12)=0 are x= 1/2+i 3/2 ,x= 1/2-i 3/2
Find the zeros of (5x+2)+(x^2-9)+(x^2-7x+12)=0
The zeros of (5x+2)+(x^2-9)+(x^2-7x+12)=0 are x= 1/2+i 3/2 ,x= 1/2-i 3/2