What are the solutions to the equation (x+4)^2-3=22 ?

The solutions to the equation (x+4)^2-3=22 are x=1,x=-9

Find the zeros of (x+4)^2-3=22

The zeros of (x+4)^2-3=22 are x=1,x=-9

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(x + 4)^{2} - 3 = 22

x = 1, x = - 9

Solution steps

(x + 4)^{2} - 3 = 22

Move

3

to the right side

(x + 4)^{2} = 25

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

x + 4 = 25 : x = 1

Solve

x + 4 = - 25 : x = - 9

The solutions to the quadratic equation are:

x = 1, x = - 9

x^{2} - 12 x = - 15

8 b + b^{2} - 10 = 0

(- \frac{12}{13})^{2} + x^{2} = 1

\frac{1}{2} x^{2} + 7 x = 0

x^{2} - 3 x - 44 = - 3 x + 5 - 3 x + 5

What are the solutions to the equation (x+4)^2-3=22 ?
The solutions to the equation (x+4)^2-3=22 are x=1,x=-9
Find the zeros of (x+4)^2-3=22
The zeros of (x+4)^2-3=22 are x=1,x=-9