What are the solutions to the equation 9x^2-10x+1=0 ?

The solutions to the equation 9x^2-10x+1=0 are x=1,x= 1/9

Find the zeros of 9x^2-10x+1=0

The zeros of 9x^2-10x+1=0 are x=1,x= 1/9

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9 x^{2} - 10 x + 1 = 0

x = 1, x = \frac{1}{9}

Decimal Notation

x = 1, x = 0.11111 \dots

Solution steps

9 x^{2} - 10 x + 1 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 10 ) \pm ( - 10 ) ^{2} - 4 \cdot 9 \cdot 1}{2 \cdot 9}

(- 10)^{2} - 4 \cdot 9 \cdot 1 = 8

x_{1, 2} = \frac{- ( - 10 ) \pm 8}{2 \cdot 9}

Separate the solutions

x_{1} = \frac{- ( - 10 ) + 8}{2 \cdot 9}, x_{2} = \frac{- ( - 10 ) - 8}{2 \cdot 9}

x = \frac{- ( - 10 ) + 8}{2 \cdot 9} : 1

x = \frac{- ( - 10 ) - 8}{2 \cdot 9} : \frac{1}{9}

The solutions to the quadratic equation are:

x = 1, x = \frac{1}{9}

x^{2} - 121 = 0

\frac{x}{3.2} = \frac{x ^{2}}{7.5}

x^{2} + 50 x - 600 = 0

2 (x - 4)^{2} - 5 = 3

- 0.008 x^{2} + 250 = 0.0016 x^{2} + 0.04 x + 150

What are the solutions to the equation 9x^2-10x+1=0 ?
The solutions to the equation 9x^2-10x+1=0 are x=1,x= 1/9
Find the zeros of 9x^2-10x+1=0
The zeros of 9x^2-10x+1=0 are x=1,x= 1/9