What are the solutions to the equation x^2+17x+12=-3x^2 ?

The solutions to the equation x^2+17x+12=-3x^2 are x=(-17+sqrt(97))/8 ,x=(-17-sqrt(97))/8

Find the zeros of x^2+17x+12=-3x^2

The zeros of x^2+17x+12=-3x^2 are x=(-17+sqrt(97))/8 ,x=(-17-sqrt(97))/8

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x^{2} + 17 x + 12 = - 3 x^{2}

x = \frac{- 17 + 97}{8}, x = \frac{- 17 - 97}{8}

Decimal Notation

x = - 0.89389 \dots, x = - 3.35610 \dots

Solution steps

x^{2} + 17 x + 12 = - 3 x^{2}

Move

3 x^{2}

to the left side

4 x^{2} + 17 x + 12 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 17 \pm 1 7 ^{2} - 4 \cdot 4 \cdot 12}{2 \cdot 4}

1 7^{2} - 4 \cdot 4 \cdot 12 = 97

x_{1, 2} = \frac{- 17 \pm 97}{2 \cdot 4}

Separate the solutions

x_{1} = \frac{- 17 + 97}{2 \cdot 4}, x_{2} = \frac{- 17 - 97}{2 \cdot 4}

x = \frac{- 17 + 97}{2 \cdot 4} : \frac{- 17 + 97}{8}

x = \frac{- 17 - 97}{2 \cdot 4} : \frac{- 17 - 97}{8}

The solutions to the quadratic equation are:

x = \frac{- 17 + 97}{8}, x = \frac{- 17 - 97}{8}

(x - 4) (x + 4) = 9

(x - 4) (x + 4) = 0

- 2 x^{2} + 16 x - 29

x^{2} + 54 = 0

A = π r^{2}, r

What are the solutions to the equation x^2+17x+12=-3x^2 ?
The solutions to the equation x^2+17x+12=-3x^2 are x=(-17+sqrt(97))/8 ,x=(-17-sqrt(97))/8
Find the zeros of x^2+17x+12=-3x^2
The zeros of x^2+17x+12=-3x^2 are x=(-17+sqrt(97))/8 ,x=(-17-sqrt(97))/8