What are the solutions to the equation x^2-25=(a+b)(a-c) ?

The solutions to the equation x^2-25=(a+b)(a-c) are x=sqrt((a+b)(a-c)+25),x=-sqrt((a+b)(a-c)+25)

Find the zeros of x^2-25=(a+b)(a-c)

The zeros of x^2-25=(a+b)(a-c) are x=sqrt((a+b)(a-c)+25),x=-sqrt((a+b)(a-c)+25)

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x^{2} - 25 = (a + b) (a - c)

x = (a + b) (a - c) + 25, x = - (a + b) (a - c) + 25

Solution steps

x^{2} - 25 = (a + b) (a - c)

Move

25

to the right side

x^{2} = (a + b) (a - c) + 25

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = (a + b) (a - c) + 25, x = - (a + b) (a - c) + 25

- 2 x^{2} + 12 x - 20 = 0

2 x^{2} - 15 = 65

(2 x + 1) \cdot (x + 3) - x \cdot (x - 2) = 0

x^{2} + 10 x + 12 = 2 x + 52 x + 5

22 - [3 x - (2 x - 1)] = 5 x + {6 - [2 x - 7] (x - 1)}

What are the solutions to the equation x^2-25=(a+b)(a-c) ?
The solutions to the equation x^2-25=(a+b)(a-c) are x=sqrt((a+b)(a-c)+25),x=-sqrt((a+b)(a-c)+25)
Find the zeros of x^2-25=(a+b)(a-c)
The zeros of x^2-25=(a+b)(a-c) are x=sqrt((a+b)(a-c)+25),x=-sqrt((a+b)(a-c)+25)