What are the solutions to the equation 1/3 (x+5)^2=7 ?

The solutions to the equation 1/3 (x+5)^2=7 are x=sqrt(21)-5,x=-sqrt(21)-5

Find the zeros of 1/3 (x+5)^2=7

The zeros of 1/3 (x+5)^2=7 are x=sqrt(21)-5,x=-sqrt(21)-5

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\frac{1}{3} (x + 5)^{2} = 7

x = 21 - 5, x = - 21 - 5

Decimal Notation

x = - 0.41742 \dots, x = - 9.58257 \dots

Solution steps

\frac{1}{3} (x + 5)^{2} = 7

Multiply both sides by

3

(x + 5)^{2} = 21

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

x + 5 = 21 : x = 21 - 5

Solve

x + 5 = - 21 : x = - 21 - 5

The solutions to the quadratic equation are:

x = 21 - 5, x = - 21 - 5

x, x^{2} + y^{2} = e^{- z}

2 x^{2} - 1 = 2 x + 3

x^{2} - x + \frac{1}{6} = 0

z^{2} - 4 z = 0

y^{2} + 12 y

What are the solutions to the equation 1/3 (x+5)^2=7 ?
The solutions to the equation 1/3 (x+5)^2=7 are x=sqrt(21)-5,x=-sqrt(21)-5
Find the zeros of 1/3 (x+5)^2=7
The zeros of 1/3 (x+5)^2=7 are x=sqrt(21)-5,x=-sqrt(21)-5