What are the solutions to the equation 32-2x^2=0 ?

The solutions to the equation 32-2x^2=0 are x=4,x=-4

Find the zeros of 32-2x^2=0

The zeros of 32-2x^2=0 are x=4,x=-4

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32 - 2 x^{2} = 0

x = 4, x = - 4

Solution steps

32 - 2 x^{2} = 0

Move

32

to the right side

- 2 x^{2} = - 32

Divide both sides by

- 2

x^{2} = 16

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = 16, x = - 16

16 = 4

- 16 = - 4

x = 4, x = - 4

0 = 5 x^{2} + 35 x - 90

x^{2} - 4 x + 1 = 0

w^{2} + 6 w - 11 = 0

x^{2} - 4 x + 3 = 0

- 9 x^{2} = 0

What are the solutions to the equation 32-2x^2=0 ?
The solutions to the equation 32-2x^2=0 are x=4,x=-4
Find the zeros of 32-2x^2=0
The zeros of 32-2x^2=0 are x=4,x=-4