What are the solutions to the equation 0=x^2+x+3 ?

The solutions to the equation 0=x^2+x+3 are x=-1/2+i(sqrt(11))/2 ,x=-1/2-i(sqrt(11))/2

Find the zeros of 0=x^2+x+3

The zeros of 0=x^2+x+3 are x=-1/2+i(sqrt(11))/2 ,x=-1/2-i(sqrt(11))/2

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0 = x^{2} + x + 3

x = - \frac{1}{2} + i \frac{11}{2}, x = - \frac{1}{2} - i \frac{11}{2}

Solution steps

0 = x^{2} + x + 3

Switch sides

x^{2} + x + 3 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 1 \pm 1 ^{2} - 4 \cdot 1 \cdot 3}{2 \cdot 1}

Simplify

1^{2} - 4 \cdot 1 \cdot 3 : 11 i

x_{1, 2} = \frac{- 1 \pm 11 i}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 1 + 11 i}{2 \cdot 1}, x_{2} = \frac{- 1 - 11 i}{2 \cdot 1}

x = \frac{- 1 + 11 i}{2 \cdot 1} : - \frac{1}{2} + i \frac{11}{2}

x = \frac{- 1 - 11 i}{2 \cdot 1} : - \frac{1}{2} - i \frac{11}{2}

The solutions to the quadratic equation are:

x = - \frac{1}{2} + i \frac{11}{2}, x = - \frac{1}{2} - i \frac{11}{2}

2 (x + 1)^{2} + 5 = 55

- 2 x^{2} + 7 x = 14

x, x^{2} y^{2} - x - y^{2} = 0

5 (x - 4)^{2} - 7 = 13

b, m = b^{2} L p

What are the solutions to the equation 0=x^2+x+3 ?
The solutions to the equation 0=x^2+x+3 are x=-1/2+i(sqrt(11))/2 ,x=-1/2-i(sqrt(11))/2
Find the zeros of 0=x^2+x+3
The zeros of 0=x^2+x+3 are x=-1/2+i(sqrt(11))/2 ,x=-1/2-i(sqrt(11))/2