What are the solutions to the equation -2x^2+7x=14 ?

The solutions to the equation -2x^2+7x=14 are x= 7/4-i(3sqrt(7))/4 ,x= 7/4+i(3sqrt(7))/4

Find the zeros of -2x^2+7x=14

The zeros of -2x^2+7x=14 are x= 7/4-i(3sqrt(7))/4 ,x= 7/4+i(3sqrt(7))/4

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- 2 x^{2} + 7 x = 14

x = \frac{7}{4} - i \frac{3 7}{4}, x = \frac{7}{4} + i \frac{3 7}{4}

Solution steps

- 2 x^{2} + 7 x = 14

Move

14

to the left side

- 2 x^{2} + 7 x - 14 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 7 \pm 7 ^{2} - 4 ( - 2 ) ( - 14 )}{2 ( - 2 )}

Simplify

7^{2} - 4 (- 2) (- 14) : 37 i

x_{1, 2} = \frac{- 7 \pm 3 7 i}{2 ( - 2 )}

Separate the solutions

x_{1} = \frac{- 7 + 3 7 i}{2 ( - 2 )}, x_{2} = \frac{- 7 - 3 7 i}{2 ( - 2 )}

x = \frac{- 7 + 3 7 i}{2 ( - 2 )} : \frac{7}{4} - i \frac{3 7}{4}

x = \frac{- 7 - 3 7 i}{2 ( - 2 )} : \frac{7}{4} + i \frac{3 7}{4}

The solutions to the quadratic equation are:

x = \frac{7}{4} - i \frac{3 7}{4}, x = \frac{7}{4} + i \frac{3 7}{4}

x, x^{2} y^{2} - x - y^{2} = 0

5 (x - 4)^{2} - 7 = 13

b, m = b^{2} L p

9 x^{2} - 24 x = - 16

a, a^{2} - b^{2} + a + b = 0

What are the solutions to the equation -2x^2+7x=14 ?
The solutions to the equation -2x^2+7x=14 are x= 7/4-i(3sqrt(7))/4 ,x= 7/4+i(3sqrt(7))/4
Find the zeros of -2x^2+7x=14
The zeros of -2x^2+7x=14 are x= 7/4-i(3sqrt(7))/4 ,x= 7/4+i(3sqrt(7))/4