What are the solutions to the equation solvefor a,a^2-b^2+a+b=0 ?

The solutions to the equation solvefor a,a^2-b^2+a+b=0 are a=-b,a=b-1

Find the zeros of solvefor a,a^2-b^2+a+b=0

The zeros of solvefor a,a^2-b^2+a+b=0 are a=-b,a=b-1

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solve for

a, a^{2} - b^{2} + a + b = 0

a = - b, a = b - 1

Solution steps

a^{2} - b^{2} + a + b = 0

Write in the standard form

a x^{2} + b x + c = 0

a^{2} + a - b^{2} + b = 0

Factor

a^{2} + a - b^{2} + b : (a + b) (a - b + 1)

(a + b) (a - b + 1) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

a + b = 0 or a - b + 1 = 0

Solve

a + b = 0 : a = - b

Solve

a - b + 1 = 0 : a = b - 1

The solutions to the quadratic equation are:

a = - b, a = b - 1

6 u^{2} + 18 u = 0

3 x^{2} + 17 x = 10

2 (x + 3) (x + 7) = 0

8 + 6 x + x^{2} = 0

x^{2} - 10 x + 1 = 20

What are the solutions to the equation solvefor a,a^2-b^2+a+b=0 ?
The solutions to the equation solvefor a,a^2-b^2+a+b=0 are a=-b,a=b-1
Find the zeros of solvefor a,a^2-b^2+a+b=0
The zeros of solvefor a,a^2-b^2+a+b=0 are a=-b,a=b-1