What are the solutions to the equation 3x^2+17x=10 ?

The solutions to the equation 3x^2+17x=10 are x=(-17+sqrt(409))/6 ,x=(-17-sqrt(409))/6

Find the zeros of 3x^2+17x=10

The zeros of 3x^2+17x=10 are x=(-17+sqrt(409))/6 ,x=(-17-sqrt(409))/6

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3 x^{2} + 17 x = 10

x = \frac{- 17 + 409}{6}, x = \frac{- 17 - 409}{6}

Decimal Notation

x = 0.53729 \dots, x = - 6.20395 \dots

Solution steps

3 x^{2} + 17 x = 10

Move

10

to the left side

3 x^{2} + 17 x - 10 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 17 \pm 1 7 ^{2} - 4 \cdot 3 ( - 10 )}{2 \cdot 3}

1 7^{2} - 4 \cdot 3 (- 10) = 409

x_{1, 2} = \frac{- 17 \pm 409}{2 \cdot 3}

Separate the solutions

x_{1} = \frac{- 17 + 409}{2 \cdot 3}, x_{2} = \frac{- 17 - 409}{2 \cdot 3}

x = \frac{- 17 + 409}{2 \cdot 3} : \frac{- 17 + 409}{6}

x = \frac{- 17 - 409}{2 \cdot 3} : \frac{- 17 - 409}{6}

The solutions to the quadratic equation are:

x = \frac{- 17 + 409}{6}, x = \frac{- 17 - 409}{6}

2 (x + 3) (x + 7) = 0

8 + 6 x + x^{2} = 0

x^{2} - 10 x + 1 = 20

- 9 x^{2} + 6 x + 15

(x + 6)^{2} = 1

What are the solutions to the equation 3x^2+17x=10 ?
The solutions to the equation 3x^2+17x=10 are x=(-17+sqrt(409))/6 ,x=(-17-sqrt(409))/6
Find the zeros of 3x^2+17x=10
The zeros of 3x^2+17x=10 are x=(-17+sqrt(409))/6 ,x=(-17-sqrt(409))/6