What are the solutions to the equation x^2-10x+1=20 ?

The solutions to the equation x^2-10x+1=20 are x=5+2sqrt(11),x=5-2sqrt(11)

Find the zeros of x^2-10x+1=20

The zeros of x^2-10x+1=20 are x=5+2sqrt(11),x=5-2sqrt(11)

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x^{2} - 10 x + 1 = 20

x = 5 + 211, x = 5 - 211

Decimal Notation

x = 11.63324 \dots, x = - 1.63324 \dots

Solution steps

x^{2} - 10 x + 1 = 20

Move

20

to the left side

x^{2} - 10 x - 19 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 10 ) \pm ( - 10 ) ^{2} - 4 \cdot 1 \cdot ( - 19 )}{2 \cdot 1}

(- 10)^{2} - 4 \cdot 1 \cdot (- 19) = 411

x_{1, 2} = \frac{- ( - 10 ) \pm 4 11}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 10 ) + 4 11}{2 \cdot 1}, x_{2} = \frac{- ( - 10 ) - 4 11}{2 \cdot 1}

x = \frac{- ( - 10 ) + 4 11}{2 \cdot 1} : 5 + 211

x = \frac{- ( - 10 ) - 4 11}{2 \cdot 1} : 5 - 211

The solutions to the quadratic equation are:

x = 5 + 211, x = 5 - 211

- 9 x^{2} + 6 x + 15

(x + 6)^{2} = 1

z^{2} - 8 z

4 x + 4 x^{2} = - 1

(x - 3)^{2} + 2 = 18

What are the solutions to the equation x^2-10x+1=20 ?
The solutions to the equation x^2-10x+1=20 are x=5+2sqrt(11),x=5-2sqrt(11)
Find the zeros of x^2-10x+1=20
The zeros of x^2-10x+1=20 are x=5+2sqrt(11),x=5-2sqrt(11)