What are the solutions to the equation (x-3)^2+2=18 ?

The solutions to the equation (x-3)^2+2=18 are x=7,x=-1

Find the zeros of (x-3)^2+2=18

The zeros of (x-3)^2+2=18 are x=7,x=-1

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(x - 3)^{2} + 2 = 18

x = 7, x = - 1

Solution steps

(x - 3)^{2} + 2 = 18

Move

2

to the right side

(x - 3)^{2} = 16

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

x - 3 = 16 : x = 7

Solve

x - 3 = - 16 : x = - 1

The solutions to the quadratic equation are:

x = 7, x = - 1

x^{2} + 2 - 6 x = 0

3 + 4 x - 4 x^{2}

(4 x - 3)^{2} = 9

(3 x + 1)^{2} - (3 x - 1)^{2} - 5 (2 x - 1) = (x + 1)^{2}

4 = c^{2}

What are the solutions to the equation (x-3)^2+2=18 ?
The solutions to the equation (x-3)^2+2=18 are x=7,x=-1
Find the zeros of (x-3)^2+2=18
The zeros of (x-3)^2+2=18 are x=7,x=-1