What are the solutions to the equation (4x-3)^2=9 ?

The solutions to the equation (4x-3)^2=9 are x= 3/2 ,x=0

Find the zeros of (4x-3)^2=9

The zeros of (4x-3)^2=9 are x= 3/2 ,x=0

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(4 x - 3)^{2} = 9

x = \frac{3}{2}, x = 0

Decimal Notation

x = 1.5, x = 0

Solution steps

(4 x - 3)^{2} = 9

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

4 x - 3 = 9 : x = \frac{3}{2}

Solve

4 x - 3 = - 9 : x = 0

The solutions to the quadratic equation are:

x = \frac{3}{2}, x = 0

(3 x + 1)^{2} - (3 x - 1)^{2} - 5 (2 x - 1) = (x + 1)^{2}

4 = c^{2}

m^{2} - 12 m + 36 = 0

6 k^{2} - 14 k + 56 = 7 + 5 k^{2}

81 - 4 x^{2} = 0

What are the solutions to the equation (4x-3)^2=9 ?
The solutions to the equation (4x-3)^2=9 are x= 3/2 ,x=0
Find the zeros of (4x-3)^2=9
The zeros of (4x-3)^2=9 are x= 3/2 ,x=0