What are the solutions to the equation 6k^2-14k+56=7+5k^2 ?

The solutions to the equation 6k^2-14k+56=7+5k^2 are k=7

Find the zeros of 6k^2-14k+56=7+5k^2

The zeros of 6k^2-14k+56=7+5k^2 are k=7

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6 k^{2} - 14 k + 56 = 7 + 5 k^{2}

k = 7

Solution steps

6 k^{2} - 14 k + 56 = 7 + 5 k^{2}

Move

5 k^{2}

to the left side

k^{2} - 14 k + 56 = 7

Move

7

to the left side

k^{2} - 14 k + 49 = 0

Solve with the quadratic formula

k_{1, 2} = \frac{- ( - 14 ) \pm ( - 14 ) ^{2} - 4 \cdot 1 \cdot 49}{2 \cdot 1}

(- 14)^{2} - 4 \cdot 1 \cdot 49 = 0

k_{1, 2} = \frac{- ( - 14 ) \pm 0}{2 \cdot 1}

k = \frac{- ( - 14 )}{2 \cdot 1}

\frac{- ( - 14 )}{2 \cdot 1} = 7

k = 7

The solution to the quadratic equation is:

k = 7

81 - 4 x^{2} = 0

2 x [x - 3] - 2 = 0

5 x^{2} - 10 x = - 5

4 + 49 y^{2} = 0

x (x + 6) = 91

What are the solutions to the equation 6k^2-14k+56=7+5k^2 ?
The solutions to the equation 6k^2-14k+56=7+5k^2 are k=7
Find the zeros of 6k^2-14k+56=7+5k^2
The zeros of 6k^2-14k+56=7+5k^2 are k=7