What are the solutions to the equation solvefor D,(2D-1)^2y=0 ?

The solutions to the equation solvefor D,(2D-1)^2y=0 are D= 1/2

Find the zeros of solvefor D,(2D-1)^2y=0

The zeros of solvefor D,(2D-1)^2y=0 are D= 1/2

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solve for

D, (2 D - 1)^{2} y = 0

D = \frac{1}{2}

Decimal Notation

D = 0.5

Solution steps

(2 D - 1)^{2} y = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

(2 D - 1)^{2} = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

Solve

2 D - 1 = 0 : D = \frac{1}{2}

The solution to the quadratic equation is:

D = \frac{1}{2}

4 x^{2} - 4 x - 5 = 0

x^{2} - 1 = - 7 x

x^{2} - 4 x + 4 = 2 x

- x^{2} + 8 x + 5 = 0

x (5 x - 8) = 13

What are the solutions to the equation solvefor D,(2D-1)^2y=0 ?
The solutions to the equation solvefor D,(2D-1)^2y=0 are D= 1/2
Find the zeros of solvefor D,(2D-1)^2y=0
The zeros of solvefor D,(2D-1)^2y=0 are D= 1/2