What are the solutions to the equation completesquare x^2-4x+4=2x ?

The solutions to the equation completesquare x^2-4x+4=2x are x=sqrt(5)+3,x=-sqrt(5)+3

Find the zeros of completesquare x^2-4x+4=2x

The zeros of completesquare x^2-4x+4=2x are x=sqrt(5)+3,x=-sqrt(5)+3

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x^{2} - 4 x + 4 = 2 x

x = 5 + 3, x = - 5 + 3

Decimal Notation

x = 5.23606 \dots, x = 0.76393 \dots

Solution steps

x^{2} - 4 x + 4 = 2 x

Move

4

to the right side

x^{2} - 4 x = 2 x - 4

Move

2 x

to the left side

x^{2} - 6 x = - 4

Rewrite in the form

(x + a)^{2} = b

(x - 3)^{2} = 5

For

the solutions are

f (x) = a, - a

Solve

x - 3 = 5 : x = 5 + 3

Solve

x - 3 = - 5 : x = - 5 + 3

The solutions to the quadratic equation are:

x = 5 + 3, x = - 5 + 3

- x^{2} + 8 x + 5 = 0

x (5 x - 8) = 13

y^{2} - 3 y - 18 = 0

1 3^{2} - 5^{2} = x^{2}

2 x^{2} + 4 x + 7

What are the solutions to the equation completesquare x^2-4x+4=2x ?
The solutions to the equation completesquare x^2-4x+4=2x are x=sqrt(5)+3,x=-sqrt(5)+3
Find the zeros of completesquare x^2-4x+4=2x
The zeros of completesquare x^2-4x+4=2x are x=sqrt(5)+3,x=-sqrt(5)+3