What are the solutions to the equation 3x^2-15x=20 ?

The solutions to the equation 3x^2-15x=20 are x=(15+sqrt(465))/6 ,x=(15-sqrt(465))/6

Find the zeros of 3x^2-15x=20

The zeros of 3x^2-15x=20 are x=(15+sqrt(465))/6 ,x=(15-sqrt(465))/6

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3 x^{2} - 15 x = 20

x = \frac{15 + 465}{6}, x = \frac{15 - 465}{6}

Decimal Notation

x = 6.09397 \dots, x = - 1.09397 \dots

Solution steps

3 x^{2} - 15 x = 20

Move

20

to the left side

3 x^{2} - 15 x - 20 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 15 ) \pm ( - 15 ) ^{2} - 4 \cdot 3 ( - 20 )}{2 \cdot 3}

(- 15)^{2} - 4 \cdot 3 (- 20) = 465

x_{1, 2} = \frac{- ( - 15 ) \pm 465}{2 \cdot 3}

Separate the solutions

x_{1} = \frac{- ( - 15 ) + 465}{2 \cdot 3}, x_{2} = \frac{- ( - 15 ) - 465}{2 \cdot 3}

x = \frac{- ( - 15 ) + 465}{2 \cdot 3} : \frac{15 + 465}{6}

x = \frac{- ( - 15 ) - 465}{2 \cdot 3} : \frac{15 - 465}{6}

The solutions to the quadratic equation are:

x = \frac{15 + 465}{6}, x = \frac{15 - 465}{6}

7 - 10 u^{2} = 1

12 x^{2} - 17 x - 5 = 0

y^{2} + 8 y + 14 = 0

y, \frac{x ^{2}}{4} + \frac{y ^{2}}{9} = 1

(2 x + 5)^{2} = 0

What are the solutions to the equation 3x^2-15x=20 ?
The solutions to the equation 3x^2-15x=20 are x=(15+sqrt(465))/6 ,x=(15-sqrt(465))/6
Find the zeros of 3x^2-15x=20
The zeros of 3x^2-15x=20 are x=(15+sqrt(465))/6 ,x=(15-sqrt(465))/6