What are the solutions to the equation -2x^2+x+7=0 ?

The solutions to the equation -2x^2+x+7=0 are x=-(-1+sqrt(57))/4 ,x=(1+sqrt(57))/4

Find the zeros of -2x^2+x+7=0

The zeros of -2x^2+x+7=0 are x=-(-1+sqrt(57))/4 ,x=(1+sqrt(57))/4

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- 2 x^{2} + x + 7 = 0

x = - \frac{- 1 + 57}{4}, x = \frac{1 + 57}{4}

Decimal Notation

x = - 1.63745 \dots, x = 2.13745 \dots

Solution steps

- 2 x^{2} + x + 7 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 1 \pm 1 ^{2} - 4 ( - 2 ) \cdot 7}{2 ( - 2 )}

1^{2} - 4 (- 2) \cdot 7 = 57

x_{1, 2} = \frac{- 1 \pm 57}{2 ( - 2 )}

Separate the solutions

x_{1} = \frac{- 1 + 57}{2 ( - 2 )}, x_{2} = \frac{- 1 - 57}{2 ( - 2 )}

x = \frac{- 1 + 57}{2 ( - 2 )} : - \frac{- 1 + 57}{4}

x = \frac{- 1 - 57}{2 ( - 2 )} : \frac{1 + 57}{4}

The solutions to the quadratic equation are:

x = - \frac{- 1 + 57}{4}, x = \frac{1 + 57}{4}

x^{2} + 3 x - 2 = 0, 5 x^{2} - 8 (x - 2) + 7 (x + 1) = x^{2} - 2

x, 8 x^{2} + 12 x y - 80 y^{2} = 0

v^{2} - 13 v + 8 = - 4

2 x^{2} + 5 x - 7

x^{2} + 8 = 4 x

What are the solutions to the equation -2x^2+x+7=0 ?
The solutions to the equation -2x^2+x+7=0 are x=-(-1+sqrt(57))/4 ,x=(1+sqrt(57))/4
Find the zeros of -2x^2+x+7=0
The zeros of -2x^2+x+7=0 are x=-(-1+sqrt(57))/4 ,x=(1+sqrt(57))/4