What are the solutions to the equation -x^2-7x=6 ?

The solutions to the equation -x^2-7x=6 are x=-6,x=-1

Find the zeros of -x^2-7x=6

The zeros of -x^2-7x=6 are x=-6,x=-1

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- x^{2} - 7 x = 6

x = - 6, x = - 1

Solution steps

- x^{2} - 7 x = 6

Move

6

to the left side

- x^{2} - 7 x - 6 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 7 ) \pm ( - 7 ) ^{2} - 4 ( - 1 ) ( - 6 )}{2 ( - 1 )}

(- 7)^{2} - 4 (- 1) (- 6) = 5

x_{1, 2} = \frac{- ( - 7 ) \pm 5}{2 ( - 1 )}

Separate the solutions

x_{1} = \frac{- ( - 7 ) + 5}{2 ( - 1 )}, x_{2} = \frac{- ( - 7 ) - 5}{2 ( - 1 )}

x = \frac{- ( - 7 ) + 5}{2 ( - 1 )} : - 6

x = \frac{- ( - 7 ) - 5}{2 ( - 1 )} : - 1

The solutions to the quadratic equation are:

x = - 6, x = - 1

\frac{x}{5000} = \frac{4}{2000} (5 - x - 0.3)^{2}

2 (x - 1)^{2} + 3 = 6

(- 1 - x) (- 1 - x) = 0

7 m^{2} = 35

t, p = - 0.4 t^{2} + 128 t + 1200

What are the solutions to the equation -x^2-7x=6 ?
The solutions to the equation -x^2-7x=6 are x=-6,x=-1
Find the zeros of -x^2-7x=6
The zeros of -x^2-7x=6 are x=-6,x=-1