What are the solutions to the equation q^2+20q=341 ?

The solutions to the equation q^2+20q=341 are q=11,q=-31

Find the zeros of q^2+20q=341

The zeros of q^2+20q=341 are q=11,q=-31

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q^{2} + 20 q = 341

q = 11, q = - 31

Solution steps

q^{2} + 20 q = 341

Move

341

to the left side

q^{2} + 20 q - 341 = 0

Solve with the quadratic formula

q_{1, 2} = \frac{- 20 \pm 2 0 ^{2} - 4 \cdot 1 \cdot ( - 341 )}{2 \cdot 1}

2 0^{2} - 4 \cdot 1 \cdot (- 341) = 42

q_{1, 2} = \frac{- 20 \pm 42}{2 \cdot 1}

Separate the solutions

q_{1} = \frac{- 20 + 42}{2 \cdot 1}, q_{2} = \frac{- 20 - 42}{2 \cdot 1}

q = \frac{- 20 + 42}{2 \cdot 1} : 11

q = \frac{- 20 - 42}{2 \cdot 1} : - 31

The solutions to the quadratic equation are:

q = 11, q = - 31

5 x^{2} + 15 x - 48 = 2

5 = 3 x^{2} - 36 x + 108

y^{2} - 3 = - 2 y

(x - 1) (x + 3) = 5

3 x^{2} - 4 x + 12 = 0

What are the solutions to the equation q^2+20q=341 ?
The solutions to the equation q^2+20q=341 are q=11,q=-31
Find the zeros of q^2+20q=341
The zeros of q^2+20q=341 are q=11,q=-31