What are the solutions to the equation 4x^2+31x+21=0 ?

The solutions to the equation 4x^2+31x+21=0 are x=-3/4 ,x=-7

Find the zeros of 4x^2+31x+21=0

The zeros of 4x^2+31x+21=0 are x=-3/4 ,x=-7

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4 x^{2} + 31 x + 21 = 0

x = - \frac{3}{4}, x = - 7

Decimal Notation

x = - 0.75, x = - 7

Solution steps

4 x^{2} + 31 x + 21 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 31 \pm 3 1 ^{2} - 4 \cdot 4 \cdot 21}{2 \cdot 4}

3 1^{2} - 4 \cdot 4 \cdot 21 = 25

x_{1, 2} = \frac{- 31 \pm 25}{2 \cdot 4}

Separate the solutions

x_{1} = \frac{- 31 + 25}{2 \cdot 4}, x_{2} = \frac{- 31 - 25}{2 \cdot 4}

x = \frac{- 31 + 25}{2 \cdot 4} : - \frac{3}{4}

x = \frac{- 31 - 25}{2 \cdot 4} : - 7

The solutions to the quadratic equation are:

x = - \frac{3}{4}, x = - 7

2 r^{2} + 8 r + 8 = 0

2 x^{2} - 6 x + 6 = c^{1} (x^{2} + x - 1) + c^{2} (x^{2} - x + 1)

(2 x - 10) (3 x + 12) = 0

a^{2} - 2 a = 2

x^{2} + 4 x - 16

What are the solutions to the equation 4x^2+31x+21=0 ?
The solutions to the equation 4x^2+31x+21=0 are x=-3/4 ,x=-7
Find the zeros of 4x^2+31x+21=0
The zeros of 4x^2+31x+21=0 are x=-3/4 ,x=-7