What are the solutions to the equation (x+1)^2=-5 ?

The solutions to the equation (x+1)^2=-5 are x=sqrt(5)i-1,x=-sqrt(5)i-1

Find the zeros of (x+1)^2=-5

The zeros of (x+1)^2=-5 are x=sqrt(5)i-1,x=-sqrt(5)i-1

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

(x + 1)^{2} = - 5

x = 5 i - 1, x = - 5 i - 1

Solution steps

(x + 1)^{2} = - 5

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

x + 1 = - 5 : x = 5 i - 1

Solve

x + 1 = - - 5 : x = - 5 i - 1

The solutions to the quadratic equation are:

x = 5 i - 1, x = - 5 i - 1

x^{2} + 18 x - 144 = 0

2 y^{2} - 8 y = 0

2 x^{2} + 9 x - 4 = 0

5 x^{2} + 2 = x

x^{2} + 8 x - 3 = 0

What are the solutions to the equation (x+1)^2=-5 ?
The solutions to the equation (x+1)^2=-5 are x=sqrt(5)i-1,x=-sqrt(5)i-1
Find the zeros of (x+1)^2=-5
The zeros of (x+1)^2=-5 are x=sqrt(5)i-1,x=-sqrt(5)i-1