What are the solutions to the equation x(x-2)=4 ?

The solutions to the equation x(x-2)=4 are x=1+sqrt(5),x=1-sqrt(5)

Find the zeros of x(x-2)=4

The zeros of x(x-2)=4 are x=1+sqrt(5),x=1-sqrt(5)

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x (x - 2) = 4

x = 1 + 5, x = 1 - 5

Decimal Notation

x = 3.23606 \dots, x = - 1.23606 \dots

Solution steps

x (x - 2) = 4

Expand

x (x - 2) : x^{2} - 2 x

x^{2} - 2 x = 4

Move

4

to the left side

x^{2} - 2 x - 4 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 2 ) \pm ( - 2 ) ^{2} - 4 \cdot 1 \cdot ( - 4 )}{2 \cdot 1}

(- 2)^{2} - 4 \cdot 1 \cdot (- 4) = 25

x_{1, 2} = \frac{- ( - 2 ) \pm 2 5}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 2 ) + 2 5}{2 \cdot 1}, x_{2} = \frac{- ( - 2 ) - 2 5}{2 \cdot 1}

x = \frac{- ( - 2 ) + 2 5}{2 \cdot 1} : 1 + 5

x = \frac{- ( - 2 ) - 2 5}{2 \cdot 1} : 1 - 5

The solutions to the quadratic equation are:

x = 1 + 5, x = 1 - 5

x^{2} - 2 x - 18 = 0

0.75 x^{2} - 6 x + 20 = 2.75 x + 1.5

6 y^{2} - 5 = - y

n^{2} + 7 n = 0

x, 3 x^{2} + 2 x y + y^{2} = 2

What are the solutions to the equation x(x-2)=4 ?
The solutions to the equation x(x-2)=4 are x=1+sqrt(5),x=1-sqrt(5)
Find the zeros of x(x-2)=4
The zeros of x(x-2)=4 are x=1+sqrt(5),x=1-sqrt(5)