What are the solutions to the equation 3/4 (x-6)^2+1=28 ?

The solutions to the equation 3/4 (x-6)^2+1=28 are x=12,x=0

Find the zeros of 3/4 (x-6)^2+1=28

The zeros of 3/4 (x-6)^2+1=28 are x=12,x=0

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\frac{3}{4} (x - 6)^{2} + 1 = 28

x = 12, x = 0

Solution steps

\frac{3}{4} (x - 6)^{2} + 1 = 28

Move

1

to the right side

\frac{3}{4} (x - 6)^{2} = 27

Multiply both sides by

4

3 (x - 6)^{2} = 108

Divide both sides by

3

(x - 6)^{2} = 36

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

x - 6 = 36 : x = 12

Solve

x - 6 = - 36 : x = 0

The solutions to the quadratic equation are:

x = 12, x = 0

x^{2} - 20 x + 33 = 0

0 = 2 x^{2} + 8 x + 5

0 = 2 x^{2} + 8 x + 1

x^{2} - 7 x - 2 c = 0

3 x^{2} - 11 x + 10 = 0

What are the solutions to the equation 3/4 (x-6)^2+1=28 ?
The solutions to the equation 3/4 (x-6)^2+1=28 are x=12,x=0
Find the zeros of 3/4 (x-6)^2+1=28
The zeros of 3/4 (x-6)^2+1=28 are x=12,x=0