What are the solutions to the equation x^2-7x-2c=0 ?

The solutions to the equation x^2-7x-2c=0 are x=(7+sqrt(49+8c))/2 ,x=(7-sqrt(49+8c))/2

Find the zeros of x^2-7x-2c=0

The zeros of x^2-7x-2c=0 are x=(7+sqrt(49+8c))/2 ,x=(7-sqrt(49+8c))/2

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x^{2} - 7 x - 2 c = 0

x = \frac{7 + 49 + 8 c}{2}, x = \frac{7 - 49 + 8 c}{2}

Solution steps

x^{2} - 7 x - 2 c = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 7 ) \pm ( - 7 ) ^{2} - 4 \cdot 1 \cdot ( - 2 c )}{2 \cdot 1}

Simplify

(- 7)^{2} - 4 \cdot 1 \cdot (- 2 c) : 49 + 8 c

x_{1, 2} = \frac{- ( - 7 ) \pm 49 + 8 c}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 7 ) + 49 + 8 c}{2 \cdot 1}, x_{2} = \frac{- ( - 7 ) - 49 + 8 c}{2 \cdot 1}

x = \frac{- ( - 7 ) + 49 + 8 c}{2 \cdot 1} : \frac{7 + 49 + 8 c}{2}

x = \frac{- ( - 7 ) - 49 + 8 c}{2 \cdot 1} : \frac{7 - 49 + 8 c}{2}

The solutions to the quadratic equation are:

x = \frac{7 + 49 + 8 c}{2}, x = \frac{7 - 49 + 8 c}{2}

3 x^{2} - 11 x + 10 = 0

1200 - \frac{3}{4} b^{2} = 0

0 = - x^{2} + 25

2 x (x + 5) = (x + 1)^{2} - 13

x, \frac{x ^{2}}{33} + \frac{y ^{2}}{49} = - 1

What are the solutions to the equation x^2-7x-2c=0 ?
The solutions to the equation x^2-7x-2c=0 are x=(7+sqrt(49+8c))/2 ,x=(7-sqrt(49+8c))/2
Find the zeros of x^2-7x-2c=0
The zeros of x^2-7x-2c=0 are x=(7+sqrt(49+8c))/2 ,x=(7-sqrt(49+8c))/2