What are the solutions to the equation 1200-3/4 b^2=0 ?

The solutions to the equation 1200-3/4 b^2=0 are b=40,b=-40

Find the zeros of 1200-3/4 b^2=0

The zeros of 1200-3/4 b^2=0 are b=40,b=-40

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1200 - \frac{3}{4} b^{2} = 0

b = 40, b = - 40

Solution steps

1200 - \frac{3}{4} b^{2} = 0

Move

1200

to the right side

- \frac{3}{4} b^{2} = - 1200

Multiply both sides by

4

- 3 b^{2} = - 4800

Divide both sides by

- 3

b^{2} = 1600

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

b = 1600, b = - 1600

1600 = 40

- 1600 = - 40

b = 40, b = - 40

0 = - x^{2} + 25

2 x (x + 5) = (x + 1)^{2} - 13

x, \frac{x ^{2}}{33} + \frac{y ^{2}}{49} = - 1

x, - 2 x^{2} y = y

x^{2} + 6 x - 3.25 = 0

What are the solutions to the equation 1200-3/4 b^2=0 ?
The solutions to the equation 1200-3/4 b^2=0 are b=40,b=-40
Find the zeros of 1200-3/4 b^2=0
The zeros of 1200-3/4 b^2=0 are b=40,b=-40