What are the solutions to the equation s^2+8s+32=0 ?

The solutions to the equation s^2+8s+32=0 are s=-4+4i,s=-4-4i

Find the zeros of s^2+8s+32=0

The zeros of s^2+8s+32=0 are s=-4+4i,s=-4-4i

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s^{2} + 8 s + 32 = 0

s = - 4 + 4 i, s = - 4 - 4 i

Solution steps

s^{2} + 8 s + 32 = 0

Solve with the quadratic formula

s_{1, 2} = \frac{- 8 \pm 8 ^{2} - 4 \cdot 1 \cdot 32}{2 \cdot 1}

Simplify

8^{2} - 4 \cdot 1 \cdot 32 : 8 i

s_{1, 2} = \frac{- 8 \pm 8 i}{2 \cdot 1}

Separate the solutions

s_{1} = \frac{- 8 + 8 i}{2 \cdot 1}, s_{2} = \frac{- 8 - 8 i}{2 \cdot 1}

s = \frac{- 8 + 8 i}{2 \cdot 1} : - 4 + 4 i

s = \frac{- 8 - 8 i}{2 \cdot 1} : - 4 - 4 i

The solutions to the quadratic equation are:

s = - 4 + 4 i, s = - 4 - 4 i

3 (x)^{2} - 6 x + 9 = 0

- x^{2} + 3 x + 10 = 0

y, x^{2} + x y + y^{2} = 7

16 x^{2} - 16 x + 3 = 0

3 y^{2} + 8 y + 5 = 0

What are the solutions to the equation s^2+8s+32=0 ?
The solutions to the equation s^2+8s+32=0 are s=-4+4i,s=-4-4i
Find the zeros of s^2+8s+32=0
The zeros of s^2+8s+32=0 are s=-4+4i,s=-4-4i