What are the solutions to the equation 12x^2+3x=-12 ?

The solutions to the equation 12x^2+3x=-12 are x=-1/8+i(3sqrt(7))/8 ,x=-1/8-i(3sqrt(7))/8

Find the zeros of 12x^2+3x=-12

The zeros of 12x^2+3x=-12 are x=-1/8+i(3sqrt(7))/8 ,x=-1/8-i(3sqrt(7))/8

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12 x^{2} + 3 x = - 12

x = - \frac{1}{8} + i \frac{3 7}{8}, x = - \frac{1}{8} - i \frac{3 7}{8}

Solution steps

12 x^{2} + 3 x = - 12

Move

12

to the left side

12 x^{2} + 3 x + 12 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 3 \pm 3 ^{2} - 4 \cdot 12 \cdot 12}{2 \cdot 12}

Simplify

3^{2} - 4 \cdot 12 \cdot 12 : 97 i

x_{1, 2} = \frac{- 3 \pm 9 7 i}{2 \cdot 12}

Separate the solutions

x_{1} = \frac{- 3 + 9 7 i}{2 \cdot 12}, x_{2} = \frac{- 3 - 9 7 i}{2 \cdot 12}

x = \frac{- 3 + 9 7 i}{2 \cdot 12} : - \frac{1}{8} + i \frac{3 7}{8}

x = \frac{- 3 - 9 7 i}{2 \cdot 12} : - \frac{1}{8} - i \frac{3 7}{8}

The solutions to the quadratic equation are:

x = - \frac{1}{8} + i \frac{3 7}{8}, x = - \frac{1}{8} - i \frac{3 7}{8}

t^{2} - 12 t + 32 = 0

12 t^{2} - 24 t - 40 = 0

4 x^{2} - 16 x - 128 = 0

8^{2} + 1 0^{2} = c^{2}

x^{2} - 6 x + 6

What are the solutions to the equation 12x^2+3x=-12 ?
The solutions to the equation 12x^2+3x=-12 are x=-1/8+i(3sqrt(7))/8 ,x=-1/8-i(3sqrt(7))/8
Find the zeros of 12x^2+3x=-12
The zeros of 12x^2+3x=-12 are x=-1/8+i(3sqrt(7))/8 ,x=-1/8-i(3sqrt(7))/8