What are the solutions to the equation 8^2+10^2=c^2 ?

The solutions to the equation 8^2+10^2=c^2 are c=2sqrt(41),c=-2sqrt(41)

Find the zeros of 8^2+10^2=c^2

The zeros of 8^2+10^2=c^2 are c=2sqrt(41),c=-2sqrt(41)

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8^{2} + 1 0^{2} = c^{2}

c = 241, c = - 241

Decimal Notation

c = 12.80624 \dots, c = - 12.80624 \dots

Solution steps

8^{2} + 1 0^{2} = c^{2}

Switch sides

c^{2} = 8^{2} + 1 0^{2}

Simplify

8^{2} + 1 0^{2} : 164

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

c = 164, c = - 164

164 = 241

- 164 = - 241

c = 241, c = - 241

x^{2} - 6 x + 6

3 x = x^{2} - 4

12 X - 4 - 9 X^{2} = 0

4 x^{2} - 12 x + 6 = 0

x, 5 x^{2} + 3 y^{2} + 10 x + 6 y + 14 = 0

What are the solutions to the equation 8^2+10^2=c^2 ?
The solutions to the equation 8^2+10^2=c^2 are c=2sqrt(41),c=-2sqrt(41)
Find the zeros of 8^2+10^2=c^2
The zeros of 8^2+10^2=c^2 are c=2sqrt(41),c=-2sqrt(41)