What are the solutions to the equation -x^2+50x-600=0 ?

The solutions to the equation -x^2+50x-600=0 are x=20,x=30

Find the zeros of -x^2+50x-600=0

The zeros of -x^2+50x-600=0 are x=20,x=30

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- x^{2} + 50 x - 600 = 0

x = 20, x = 30

Solution steps

- x^{2} + 50 x - 600 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 50 \pm 5 0 ^{2} - 4 ( - 1 ) ( - 600 )}{2 ( - 1 )}

5 0^{2} - 4 (- 1) (- 600) = 10

x_{1, 2} = \frac{- 50 \pm 10}{2 ( - 1 )}

Separate the solutions

x_{1} = \frac{- 50 + 10}{2 ( - 1 )}, x_{2} = \frac{- 50 - 10}{2 ( - 1 )}

x = \frac{- 50 + 10}{2 ( - 1 )} : 20

x = \frac{- 50 - 10}{2 ( - 1 )} : 30

The solutions to the quadratic equation are:

x = 20, x = 30

9 x^{2} - 36 x + 37 = 0

x, 8 x^{2} - 24 x + 10 y^{2} - 24 y + 56 = 0

5 (x + 1)^{2} = 3 x + 299

2 x^{2} - 7 x + 13 = 10

5 x^{2} + x - \frac{1}{10} = 0

What are the solutions to the equation -x^2+50x-600=0 ?
The solutions to the equation -x^2+50x-600=0 are x=20,x=30
Find the zeros of -x^2+50x-600=0
The zeros of -x^2+50x-600=0 are x=20,x=30