What are the solutions to the equation 0=-16t^2+16t+96 ?

The solutions to the equation 0=-16t^2+16t+96 are t=-2,t=3

Find the zeros of 0=-16t^2+16t+96

The zeros of 0=-16t^2+16t+96 are t=-2,t=3

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0 = - 16 t^{2} + 16 t + 96

t = - 2, t = 3

Solution steps

0 = - 16 t^{2} + 16 t + 96

Switch sides

- 16 t^{2} + 16 t + 96 = 0

Solve with the quadratic formula

t_{1, 2} = \frac{- 16 \pm 1 6 ^{2} - 4 ( - 16 ) \cdot 96}{2 ( - 16 )}

1 6^{2} - 4 (- 16) \cdot 96 = 80

t_{1, 2} = \frac{- 16 \pm 80}{2 ( - 16 )}

Separate the solutions

t_{1} = \frac{- 16 + 80}{2 ( - 16 )}, t_{2} = \frac{- 16 - 80}{2 ( - 16 )}

t = \frac{- 16 + 80}{2 ( - 16 )} : - 2

t = \frac{- 16 - 80}{2 ( - 16 )} : 3

The solutions to the quadratic equation are:

t = - 2, t = 3

x^{2} + 4 x - 45 = 0

30 x + 25 = - 9 x^{2}

4 x^{2} = 3

(5 x - 3)^{2} - 4 = 0

2 a^{2} + 4 a - 6 = 0

What are the solutions to the equation 0=-16t^2+16t+96 ?
The solutions to the equation 0=-16t^2+16t+96 are t=-2,t=3
Find the zeros of 0=-16t^2+16t+96
The zeros of 0=-16t^2+16t+96 are t=-2,t=3