What are the solutions to the equation (5x-3)^2-4=0 ?

The solutions to the equation (5x-3)^2-4=0 are x=1,x= 1/5

Find the zeros of (5x-3)^2-4=0

The zeros of (5x-3)^2-4=0 are x=1,x= 1/5

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(5 x - 3)^{2} - 4 = 0

x = 1, x = \frac{1}{5}

Decimal Notation

x = 1, x = 0.2

Solution steps

(5 x - 3)^{2} - 4 = 0

Move

4

to the right side

(5 x - 3)^{2} = 4

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

5 x - 3 = 4 : x = 1

Solve

5 x - 3 = - 4 : x = \frac{1}{5}

The solutions to the quadratic equation are:

x = 1, x = \frac{1}{5}

2 a^{2} + 4 a - 6 = 0

n^{2} - 12 n + 35 = 0

(x - 2) (x - 6) = 0

3 x^{2} + 2 x + \frac{1}{3} = 0

x, f = \frac{x ^{2}}{y - 1}

What are the solutions to the equation (5x-3)^2-4=0 ?
The solutions to the equation (5x-3)^2-4=0 are x=1,x= 1/5
Find the zeros of (5x-3)^2-4=0
The zeros of (5x-3)^2-4=0 are x=1,x= 1/5