What are the solutions to the equation 3x^2+36x=0 ?

The solutions to the equation 3x^2+36x=0 are x=0,x=-12

Find the zeros of 3x^2+36x=0

The zeros of 3x^2+36x=0 are x=0,x=-12

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3 x^{2} + 36 x = 0

x = 0, x = - 12

Solution steps

3 x^{2} + 36 x = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 36 \pm 3 6 ^{2} - 4 \cdot 3 \cdot 0}{2 \cdot 3}

3 6^{2} - 4 \cdot 3 \cdot 0 = 36

x_{1, 2} = \frac{- 36 \pm 36}{2 \cdot 3}

Separate the solutions

x_{1} = \frac{- 36 + 36}{2 \cdot 3}, x_{2} = \frac{- 36 - 36}{2 \cdot 3}

x = \frac{- 36 + 36}{2 \cdot 3} : 0

x = \frac{- 36 - 36}{2 \cdot 3} : - 12

The solutions to the quadratic equation are:

x = 0, x = - 12

v, w = u^{3} + 2 uv - 2 v^{2} - 4 u + 5

x^{2} + 10 x + 21 = 0

2 x^{2} - 2 x - 40 = 0

x - x^{2} = 4 x - 4 x^{2}

2 x^{2} = (\frac{6}{7}) x + 2

What are the solutions to the equation 3x^2+36x=0 ?
The solutions to the equation 3x^2+36x=0 are x=0,x=-12
Find the zeros of 3x^2+36x=0
The zeros of 3x^2+36x=0 are x=0,x=-12