What are the solutions to the equation m^2-15m+54=0 ?

The solutions to the equation m^2-15m+54=0 are m=9,m=6

Find the zeros of m^2-15m+54=0

The zeros of m^2-15m+54=0 are m=9,m=6

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m^{2} - 15 m + 54 = 0

m = 9, m = 6

Solution steps

m^{2} - 15 m + 54 = 0

Solve with the quadratic formula

m_{1, 2} = \frac{- ( - 15 ) \pm ( - 15 ) ^{2} - 4 \cdot 1 \cdot 54}{2 \cdot 1}

(- 15)^{2} - 4 \cdot 1 \cdot 54 = 3

m_{1, 2} = \frac{- ( - 15 ) \pm 3}{2 \cdot 1}

Separate the solutions

m_{1} = \frac{- ( - 15 ) + 3}{2 \cdot 1}, m_{2} = \frac{- ( - 15 ) - 3}{2 \cdot 1}

m = \frac{- ( - 15 ) + 3}{2 \cdot 1} : 9

m = \frac{- ( - 15 ) - 3}{2 \cdot 1} : 6

The solutions to the quadratic equation are:

m = 9, m = 6

t^{2} - 2 t = 63

x, 9 x^{2} - 54 x + 9 y^{2} + 6 y + 91 = 0

0 = 2 x^{2} - 8

2 x^{2} + 11 x - 13 = 0

x^{2} + 3 x + 2 = 0

What are the solutions to the equation m^2-15m+54=0 ?
The solutions to the equation m^2-15m+54=0 are m=9,m=6
Find the zeros of m^2-15m+54=0
The zeros of m^2-15m+54=0 are m=9,m=6