What are the solutions to the equation (3x+1)^2=6 ?

The solutions to the equation (3x+1)^2=6 are x=(sqrt(6)-1)/3 ,x=(-sqrt(6)-1)/3

Find the zeros of (3x+1)^2=6

The zeros of (3x+1)^2=6 are x=(sqrt(6)-1)/3 ,x=(-sqrt(6)-1)/3

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(3 x + 1)^{2} = 6

x = \frac{6 - 1}{3}, x = \frac{- 6 - 1}{3}

Decimal Notation

x = 0.48316 \dots, x = - 1.14982 \dots

Solution steps

(3 x + 1)^{2} = 6

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

3 x + 1 = 6 : x = \frac{6 - 1}{3}

Solve

3 x + 1 = - 6 : x = \frac{- 6 - 1}{3}

The solutions to the quadratic equation are:

x = \frac{6 - 1}{3}, x = \frac{- 6 - 1}{3}

e^{- 0.7}

8 - 2 x \leq - x + 9

\frac{x ^{2} + 5 x + 6}{x ^{2} + x - 6} \geq 0

7 x^{- 3} \cdot 4 x^{- 2}

- \frac{4 x}{5} < 0

What are the solutions to the equation (3x+1)^2=6 ?
The solutions to the equation (3x+1)^2=6 are x=(sqrt(6)-1)/3 ,x=(-sqrt(6)-1)/3
Find the zeros of (3x+1)^2=6
The zeros of (3x+1)^2=6 are x=(sqrt(6)-1)/3 ,x=(-sqrt(6)-1)/3