What are the solutions to the equation x^2-16x=60 ?

The solutions to the equation x^2-16x=60 are x=2(4+sqrt(31)),x=2(4-sqrt(31))

Find the zeros of x^2-16x=60

The zeros of x^2-16x=60 are x=2(4+sqrt(31)),x=2(4-sqrt(31))

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x^{2} - 16 x = 60

x = 2 (4 + 31), x = 2 (4 - 31)

Decimal Notation

x = 19.13552 \dots, x = - 3.13552 \dots

Solution steps

x^{2} - 16 x = 60

Move

60

to the left side

x^{2} - 16 x - 60 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 16 ) \pm ( - 16 ) ^{2} - 4 \cdot 1 \cdot ( - 60 )}{2 \cdot 1}

(- 16)^{2} - 4 \cdot 1 \cdot (- 60) = 431

x_{1, 2} = \frac{- ( - 16 ) \pm 4 31}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 16 ) + 4 31}{2 \cdot 1}, x_{2} = \frac{- ( - 16 ) - 4 31}{2 \cdot 1}

x = \frac{- ( - 16 ) + 4 31}{2 \cdot 1} : 2 (4 + 31)

x = \frac{- ( - 16 ) - 4 31}{2 \cdot 1} : 2 (4 - 31)

The solutions to the quadratic equation are:

x = 2 (4 + 31), x = 2 (4 - 31)

4 x^{2} + 8 x - 60 = 0

7 x^{2} - 9 x - 10 = 0

2 x^{2} - 6 x

p, pq x^{2} + (p^{2} - q^{2}) x = pq

12 x^{2} - 224 x + 703 = 0

What are the solutions to the equation x^2-16x=60 ?
The solutions to the equation x^2-16x=60 are x=2(4+sqrt(31)),x=2(4-sqrt(31))
Find the zeros of x^2-16x=60
The zeros of x^2-16x=60 are x=2(4+sqrt(31)),x=2(4-sqrt(31))