What are the solutions to the equation 12x^2-224x+703=0 ?

The solutions to the equation 12x^2-224x+703=0 are x=(56+sqrt(1027))/6 ,x=(56-sqrt(1027))/6

Find the zeros of 12x^2-224x+703=0

The zeros of 12x^2-224x+703=0 are x=(56+sqrt(1027))/6 ,x=(56-sqrt(1027))/6

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12 x^{2} - 224 x + 703 = 0

x = \frac{56 + 1027}{6}, x = \frac{56 - 1027}{6}

Decimal Notation

x = 14.67447 \dots, x = 3.99219 \dots

Solution steps

12 x^{2} - 224 x + 703 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 224 ) \pm ( - 224 ) ^{2} - 4 \cdot 12 \cdot 703}{2 \cdot 12}

(- 224)^{2} - 4 \cdot 12 \cdot 703 = 41027

x_{1, 2} = \frac{- ( - 224 ) \pm 4 1027}{2 \cdot 12}

Separate the solutions

x_{1} = \frac{- ( - 224 ) + 4 1027}{2 \cdot 12}, x_{2} = \frac{- ( - 224 ) - 4 1027}{2 \cdot 12}

x = \frac{- ( - 224 ) + 4 1027}{2 \cdot 12} : \frac{56 + 1027}{6}

x = \frac{- ( - 224 ) - 4 1027}{2 \cdot 12} : \frac{56 - 1027}{6}

The solutions to the quadratic equation are:

x = \frac{56 + 1027}{6}, x = \frac{56 - 1027}{6}

a, (a + b)^{2} = 81

4 = (x + 2)^{2}

2 x - 1 = x^{2} - 4 x + 4

x^{2} - 18 x + 64 = 0

(2 x + 1) (2 x - 1) = 0

What are the solutions to the equation 12x^2-224x+703=0 ?
The solutions to the equation 12x^2-224x+703=0 are x=(56+sqrt(1027))/6 ,x=(56-sqrt(1027))/6
Find the zeros of 12x^2-224x+703=0
The zeros of 12x^2-224x+703=0 are x=(56+sqrt(1027))/6 ,x=(56-sqrt(1027))/6